Craig Evans
/
1620_Lab2_Task10
Example solution
main.cpp
- Committer:
- eencae
- Date:
- 2017-02-02
- Revision:
- 0:cb82516f2dce
File content as of revision 0:cb82516f2dce:
/* ELEC1620 Lab 2 Task 10 Bit-wise Operators (c) Dr Craig A. Evans, Feb 2017 */ #include "mbed.h" int main() { char a = 34; // 0010 0010 char b = 107; // 0110 1011 printf("a = %i\n",a); printf("b = %i\n",b); printf("We'll shift a by one place to the left and store in c.\n"); printf("This is the same as multiplying by 2.\n"); char c = a << 1; // 0100 0100 = 64 + 4 = 68 printf("c = %i\n",c); printf("We'll shift b by fives place to the right and store in d.\n"); printf("This is the same as dividing by 2^5 = 32.\n"); char d = b >> 5; // 0000 0011 = 2 + 1 = 3 printf("d = %i\n",d); printf("Remember, these are integers so we lose the decimal places.\n"); printf("Now we'll set bit 6 of c using the bit-wise OR operation.\n"); char e = c | (1<<6); // 0100 0100 | 0100 0000 printf("It turns out bit 6 is already set and so the value doesn't change.\n"); printf("e = %i\n",e); printf("Finally we'll clear bit 2 of c using the bit-wise AND and NOT operation.\n"); char f = c & ~(1<<2); // 0100 0100 & 1111 1011 = 0100 0000 printf("f = %i\n",f); }