mark reilly
/
Counting_Machine_V6
final form
Diff: main.cpp
- Revision:
- 3:c9057d642843
- Parent:
- 2:c95f08525bea
- Child:
- 4:67766287a6a0
diff -r c95f08525bea -r c9057d642843 main.cpp --- a/main.cpp Tue Oct 23 09:49:35 2018 +0000 +++ b/main.cpp Tue Oct 23 12:00:45 2018 +0000 @@ -9,8 +9,8 @@ DigitalIn LDR6(p15); //50p DigitalIn LDR7(p16); //1GBP DigitalIn LDR8(p17); //2GBP //I don't know the mistake -AnalogIn button1(p18); -AnalogIn button2(p19); +DigitalIn switch1(p18); +//AnalogIn button2(p19); C12832 lcd(p5, p7, p6, p8, p11); @@ -49,7 +49,7 @@ for(;;) { - if(t > 8) + if(t > 1) { break; } @@ -139,7 +139,7 @@ ta = a[0]+a[1]+a[2]+a[3]+a[4]+a[5]+a[6]+a[7]; lcd.locate(0,0); - lcd.printf("Your total amount is %d %c",ta,char(163)); + lcd.printf("Your total value is %d %c.",ta,char(163)); wait(5); lcd.cls(); @@ -148,7 +148,7 @@ lcd.cls(); lcd.printf("Confirm your choice by using the switch."); wait(3); - + lcd.cls(); /*switch (buttons) { case button1: an = an+1; @@ -158,12 +158,13 @@ } lcd.cls(); lcd.printf("Do you want to see the number of %d coins?",v[an]); + break; case button2: lcd.printf("You have %d of this type of coins. \nThat means you have %f£ of this type of coin.",n[an],a[an]); //it doesn't know button1 and button2 yet break; }*/ - while(1) + do { - if (button1 == 1) + if (switch1 == 1) { an++; if (an > 8) @@ -175,16 +176,33 @@ wait(3); //button1 = 0; } - if (button2 == 1) + else { lcd.printf("You have %d of this type of coins. \nThat means you have %f %c of this type of coin.",n[an],a[an],char(163)); //it doesn't know button1 and button2 yet - break; + wait(5); + lcd.cls(); + lcd.printf("If you would like to see other \ntypes of coins as well, please \nuse switch again."); + wait(5); + lcd.cls(); } } - wait(5); - lcd.cls(); - lcd.printf("Thank you for using 'Coounting Machine'. \nGood Bye. :-)"); - wait(5); + while(switch1 == 1); + //wait(5); + //lcd.cls(); + + + lcd.printf("Please use the switch for finishing process."); + wait(4); + do + { + if(switch1 == 1) + { + lcd.cls(); + lcd.printf("Thank you for using 'Coounting Machine'. \nGood Bye. :-)"); + wait(5); + lcd.cls(); + } + }while (switch1 == 0); /*if() //press button or something like that //total amount which is left when the user took money and entered the amount of it in the machine. { lcd.printf("Please enter the mount of money you took:"); @@ -197,3 +215,4 @@ return(0); } +//change all 1 to 0 at LDR1,2,... \ No newline at end of file