Diff: peak.cpp

Revision:

0:59ce24b43be2

Child:

1:d1dac3b2692a

--- /dev/null	Thu Jan 01 00:00:00 1970 +0000
+++ b/peak.cpp	Mon Nov 25 14:26:44 2019 +0000
@@ -0,0 +1,90 @@
+#include "peak.h"
+#include <iostream>
+
+void PEAK::findPeaks(vector<float> num,int count, float threshold)  
+{  
+    vector<int> sign;  
+    for(int i = 1;i<count;i++)  
+    {  
+        /*do difference between the near points： 
+         *result<0，sign = -1 
+         *result>0，sign = 1 
+         *result=0，sign = 0 
+         */  
+        float diff = num[i] - num[i-1];  
+        //printf("difference:%f",diff);
+        if(diff>0)  
+        {  
+            sign.push_back(1);  
+        }  
+        else if(diff<0)  
+        {  
+            sign.push_back(-1);  
+        }  
+        else  
+        {  
+            sign.push_back(0);  
+        }  
+    }  
+    //do difference between the near sign
+    //result < 0 save the max index
+    //result > 0 save the min index 
+    vector<int> indMax;  
+    vector<int> indMin;  
+    int cnt = 0;
+    for(int j = 1;j<sign.size();j++)  
+    {  
+        int diff = sign[j]-sign[j-1];  
+        if(diff<0)  
+        {  
+            indMax.push_back(j);  
+        }  
+        else if(diff>0)  
+        {  
+            indMin.push_back(j);  
+        }  
+    }  
+    //try to find the valid max (which the previous min is smaller than threshold)
+    //begin with index 1 so there will have +1 or -1 error
+    //for(int j = 1;j<indMax.size();j++)  
+//    {
+//        
+//        for(int i =0; i <indMin.size()-1; i++)
+//        {
+//            if(indMin[i]<indMax[j] && indMin[i+1]>indMax[j] && num[indMin[i]]< threshold)
+//            {
+//                cnt = cnt +1;    
+//                printf("found a valid max, index:%d, value: %f \n\r", indMax[j],num[indMax[j]]);
+//            }    
+//        }
+//        
+//    }
+    
+    for(int j = 0; j < indMax.size(); j++)
+    {
+        
+        if(num[indMax[j]] > threshold)
+        {
+            cnt = cnt +1;    
+            //printf("found a valid max, index:%d, value: %f \n\r", indMax[j],num[indMax[j]]);
+        }
+    }
+    
+    
+    printf("num of max: %d\n\r", indMax.size());
+    printf("num of step: %d\n\r", cnt);
+    
+   // cout<<"max values:"<<endl;
+//    for(int m = 0;m<indMax.size();m++)  
+//    {  
+//        printf("index:%d, value: %f ", indMax[m],num[indMax[m]]);
+//    }  
+//    cout<<endl;  
+//    cout<<"min values："<<endl;  
+//    for(int n = 0;n<indMin.size();n++)  
+//    {  
+//        cout<<num[indMin[n]]<<"  ";  
+//    }  
+//    cout<<endl;
+}  
+