the first vision of peak detection. I try to detect the value max of a array that the previous min point is lower than a threshold given.

Revision:
0:08dd14677b02
diff -r 000000000000 -r 08dd14677b02 main.cpp
--- /dev/null	Thu Jan 01 00:00:00 1970 +0000
+++ b/main.cpp	Wed Nov 20 11:56:33 2019 +0000
@@ -0,0 +1,101 @@
+/* mbed Microcontroller Library
+ * Copyright (c) 2019 ARM Limited
+ * SPDX-License-Identifier: Apache-2.0
+ */
+
+#include "mbed.h"
+#include "platform/mbed_thread.h"
+#include <vector>  
+#include <iostream>
+
+// Blinking rate in milliseconds
+#define BLINKING_RATE_MS                                                    500
+using namespace std;
+
+void findPeaks(float *num,int count, float threshold)  
+{  
+    vector<int> sign;  
+    for(int i = 1;i<count;i++)  
+    {  
+        /*do difference between the near points: 
+         *result<0,sign = -1 
+         *result>0,sign = 1 
+         *result=0,sign = 0 
+         */  
+        int diff = num[i] - num[i-1];  
+        if(diff>0)  
+        {  
+            sign.push_back(1);  
+        }  
+        else if(diff<0)  
+        {  
+            sign.push_back(-1);  
+        }  
+        else  
+        {  
+            sign.push_back(0);  
+        }  
+    }  
+    //do difference between the near sign
+    //result < 0 save the max index
+    //result > 0 save the min index 
+    vector<int> indMax;  
+    vector<int> indMin;  
+    int cnt = 1;
+    for(int j = 1;j<sign.size();j++)  
+    {  
+        int diff = sign[j]-sign[j-1];  
+        if(diff<0)  
+        {  
+            indMax.push_back(j);  
+        }  
+        else if(diff>0)  
+        {  
+            indMin.push_back(j);  
+        }  
+    }  
+    //try to find the valid max (which the previous min is smaller than threshold)
+    //begin with index 1 so there will have +1 or -1 error
+    for(int j = 1;j<indMax.size();j++)  
+    {
+        
+        for(int i =0; i <indMin.size()-1; i++)
+        {
+            if(indMin[i]<indMax[j] && indMin[i+1]>indMax[j] && num[indMin[i]]< threshold)
+            {
+                cnt = cnt +1;    
+                printf("found a valid max, index:%d, value: %f \n\r", indMax[j],num[indMax[j]]);
+            }    
+        }
+        
+    }
+    printf("num of max: %d\n\r", indMax.size());
+    printf("num of valid max: %d\n\r", cnt);
+    
+    cout<<"max values:"<<endl;
+    for(int m = 0;m<indMax.size();m++)  
+    {  
+        cout<<num[indMax[m]]<<"  ";  
+    }  
+    cout<<endl;  
+    cout<<"min values:"<<endl;  
+    for(int n = 0;n<indMin.size();n++)  
+    {  
+        cout<<num[indMin[n]]<<"  ";  
+    }  
+    cout<<endl;
+}  
+
+int main()
+{
+    // Initialise the digital pin LED1 as an output
+    DigitalOut led(LED1);
+    float a[] = {1,2,10,2,4,0,8,10,23,0,2, 0, 5};  
+    int len = sizeof(a)/sizeof(int);
+    while (true) {
+        //printf("len of a is %d \n\r", len);
+        findPeaks(a,len,1); 
+        led = !led;
+        thread_sleep_for(BLINKING_RATE_MS);
+    }
+}