Diff: main.cpp

Revision:

0:d9d4f644fecc

Child:

1:bf8737118d3d

--- /dev/null	Thu Jan 01 00:00:00 1970 +0000
+++ b/main.cpp	Tue Oct 09 09:34:04 2018 +0000
@@ -0,0 +1,60 @@
+#include "mbed.h"
+#include "C12832.h"
+
+DigitalIn LDR1(p8);   //1p
+DigitalIn LDR2(p9);   //2p
+DigitalIn LDR3(p10);  //5p
+DigitalIn LDR4(p11);  //10p
+DigitalIn LDR5(p12);  //20p
+DigitalIn LDR6(p13);  //50p
+DigitalIn LDR7(p14);  //1GBP
+DigitalIn LDR8(p15);  //2GBP //I don't know the mistake 
+
+C12832 lcd(p5,p6,p7,p8)
+
+int main() {
+    int n1; //number of 1p coins
+    float a1; //amount of 1p coins
+    float ta; //total amount of all coins
+    int c; //counting variable
+    float tm; // token money 
+    
+    for(;;) 
+    {
+       if(LDR1 == 1)
+       {
+        a1++;
+        n1 = a1*0.01;
+        //wait(0.2); //I don't know if the programm would count a coin twice when we reset the LED immediately because the programm runs faster than the coins fall 
+        //why is LED1 = 0; a failure?
+        c = 0;
+       }
+       //... other types of coins
+       c++;
+       if (c >= 100)//depands how long the programm per cycle needs
+       {
+           break;
+       }
+    } 
+       lcd.printf("You have %d coins of 1p which means you have %d",a1,n1); // it looks like we have to use only printf and not lcd.printf
+       wait(3);
+       lcd.cls();
+       //doing these things for the other coins as well
+       
+       //ta = n1+n2+n5+n10+n20+n50+n100+n200;
+       lcd.printf("Your total amount is %d",ta);
+       wait(3);
+       lcd.cls();
+       
+       //if() //press button or something like that 
+       {
+           lcd.printf("Please enter the mount of money you took:");
+           scanf("%f",&tm);
+           lcd.printf("%f",tm);
+           wait(2);
+           ta = ta-tm;
+           lcd.printf("Now you have only %f \bx156 left", ta); //\b for one step backword and I guess that x156 for £ //I'm not sure
+       }
+       
+    return(0);
+}
\ No newline at end of file