Jon Garcia

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7 years, 7 months ago.

Coding for LED and Photo diodes with digital inputs and outputs.

I want to incorporate 6 LEDs and Photodoide but im getting errors with two inputs, how can i fix this. How can i fix this? no operator = matches these operands

  1. include "mbed.h"

DigitalOut LED_1(PTC0); DigitalIn photo_1(PTB3);

DigitalIn LED_2(PTC7); DigitalOut photo_2(PTB2);

DigitalIn LED_3(PTC3); DigitalOut photo_3(PTB1);

DigitalIn LED_4(PTC4); DigitalOut photo_4(PTB0);

DigitalIn LED_5(PTC5); DigitalOut photo_5(PTB8);

DigitalIn LED_6(PTC6); DigitalOut photo_6(PTB9);

Serial pc(USBTX, USBRX);

int input_1; int output_1;

int input_2; int output_2;

int input_3; int output_3;

int input_4; int output_4;

int input_5; int output_5;

int input_6; int output_6;

int main() {

LED_1 = 0; LED_2 = 0; LED_3 = 0; LED_4 = 0; LED_5 = 0; LED_6 = 0;

while(1) { input_1 = photo_1.read(); input_2 = photo_2.read(); input_3 = photo_3.read(); input_4 = photo_4.read(); input_5 = photo_5.read(); input_6 = photo_6.read();

if(input_1&&input_2){ LED_1 = 1; output_1 = 1; LED_2 = 1; output_2 = 1;

if(input_3){ led_3 = 1; output_3 = 1;

if(input_4){ led_4 = 1; output_4 = 1; } if(input_5){ led_5 = 1; output_5 = 1; } if(input_6){ led_6 = 1; output_6 = 1; } else LED_1 = 0; output_1 = 0;

LED_2 = 0; output_2 = 0;

LED_3 = 0; output_3 = 0;

LED_4 = 0; output_4 = 0;

LED_5 = 0; output_5 = 0;

LED_6 = 0; output_6 = 0; } pc.printf("photo: %d, led: %d\r\n",input_1,output_1);

pc.printf("photo: %d, led: %d\r\n",input_2,output_2);

pc.printf("photo: %d, led: %d\r\n",input_3,output_3);

pc.printf("photo: %d, led: %d\r\n",input_4,output_4);

pc.printf("photo: %d, led: %d\r\n",input_5,output_5);

pc.printf("photo: %d, led: %d\r\n",input_6,output_6);

wait(.5);

}

Please edit the post to use

<<code>>
your code here
<</code>>

so that the formatting is preserved otherwise it's hard to tell what's a comment and what isn't.

And please give every possible detail of the error you get rather than just the type of error. The compiler gives you a line number, it would be helpful if you told us that.

posted by Andy A 28 Apr 2017
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