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8 years ago.

Use push button for input option

I use serial for input options and run program, I don't want to use a serial. I want to use push button to specify the option

its my program now


        lcd.printf("Lama Pengujian:\n1 = 180 Menit\n2 = 300 Menit\n3 = 480 Menit %");
        wait(1.0);
        char a = pc.getc();
        if((a == '1') && k==0)
        {
            lcd.cls();
            jam=180;
            lcd.printf("Pengujian 180 Menit\n");
            wait(1.0);
        }
        if((a == '2') && k==0)
        {
            lcd.cls();
            jam=300;
            lcd.printf("Pengujian 300 Menit\n");
            wait(1.0);
        }
        if((a == '3') && k==0)
        {
            lcd.cls();
            jam=480;
            lcd.printf("Pengujian 480 Menit\n");
            wait(1.0);
        }

i want make the program will not continue if I haven't pressed the push button. how if I use a push button for input a value and run the program ?

1 Answer

Sanjiv Bhatia
8 years ago.

You are very close. You need to create a loop to read the keypress. Also, do you need the k==0 check ?

Try:

        lcd.printf("Lama Pengujian:\n1 = 180 Menit\n2 = 300 Menit\n3 = 480 Menit %");
        wait(1.0);
while(1) // permanent loop to read the keypress and then act on the value of the keypress
{
        char a = pc.getc();
        if((a == '1') && k==0)
        {
            lcd.cls();
            jam=180;
            lcd.printf("Pengujian 180 Menit\n");
            wait(1.0);
        }
        if((a == '2') && k==0)
        {
            lcd.cls();
            jam=300;
            lcd.printf("Pengujian 300 Menit\n");
            wait(1.0);
        }
        if((a == '3') && k==0)
        {
            lcd.cls();
            jam=480;
            lcd.printf("Pengujian 480 Menit\n");
            wait(1.0);
        }
 }