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8 years, 8 months ago.
How to parse variables from a void to a function
1 Answer
8 years, 8 months ago.
Your question is vague but I'm going to take a guess at what you're asking ...
typedef struct { int x; int y; int z; } thing1; typedef struct { float scale; float offset; } thing2; thing1 first = {1, 2, 3}; thing2 sec = {3.15f, -1.00f}; void myFunc(int thingType, void * pThing) { if (thingType == 1) { thing1 * ptr = (thing1 *)pThing; // the cast lets us extract meaning behind the void * printf("thing1 has (%d,%d,%d)\r\n", ptr->x, ptr->y, ptr->z); } else if (thingType == 2) { thing2 * ptr = (thing2 *)pThing; printf("thing2 has (%f,%f)\r\n", ptr->scale, ptr->offset); } else { printf("unknown thingtype\r\n"); } } ... myFunc(1, (void *)&first); ... myFunc(2, (void *)&sec); ...
Can anyone give me a hint on how this is done
posted by Hut The Nut 08 Mar 2016Can you show with some (pseudo) code what exactly you try to do?
posted by Erik - 09 Mar 2016