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8 years, 9 months ago.
How to parse variables from a void to a function
1 Answer
8 years, 9 months ago.
Your question is vague but I'm going to take a guess at what you're asking ...
typedef struct {
int x;
int y;
int z;
} thing1;
typedef struct {
float scale;
float offset;
} thing2;
thing1 first = {1, 2, 3};
thing2 sec = {3.15f, -1.00f};
void myFunc(int thingType, void * pThing) {
if (thingType == 1) {
thing1 * ptr = (thing1 *)pThing; // the cast lets us extract meaning behind the void *
printf("thing1 has (%d,%d,%d)\r\n", ptr->x, ptr->y, ptr->z);
} else if (thingType == 2) {
thing2 * ptr = (thing2 *)pThing;
printf("thing2 has (%f,%f)\r\n", ptr->scale, ptr->offset);
} else {
printf("unknown thingtype\r\n");
}
}
...
myFunc(1, (void *)&first);
...
myFunc(2, (void *)&sec);
...
Accepted Answer
Can anyone give me a hint on how this is done
posted by Hut The Nut 08 Mar 2016Can you show with some (pseudo) code what exactly you try to do?
posted by Erik - 09 Mar 2016