File content as of revision 2:370f188e2590:

#include "mbed.h"
#include "C12832.h"

DigitalIn LDR1(p9);   //1p
DigitalIn LDR2(p10);   //2p
DigitalIn LDR3(p12);  //5p
DigitalIn LDR4(p13);  //10p
DigitalIn LDR5(p14);  //20p
DigitalIn LDR6(p15);  //50p
DigitalIn LDR7(p16);  //1GBP
DigitalIn LDR8(p17);  //2GBP //I don't know the mistake 

C12832 lcd(p5,p6,p7,p8,p11);

int main() 
{
    int n1; //number of 1p coins
    float a1; //amount of 1p coins
    //...
    float ta; //total amount of all coins
    int c; //counting variable
    float tm; // token money 
    
    for(;;) 
    {
       if(LDR1 == 1)
       {
        a1++;
        n1 = a1*0.01;
        //wait(0.2); //I don't know if the programm would count a coin twice when we reset the LED immediately because the programm runs faster than the coins fall 
        //why is LED1 = 0; a failure?
        c = 0;
       }
       //... other types of coins
       c++;
       if (c >= 100)//depands how long the programm per cycle needs
       {
           break;
       }
    } 
       lcd.printf("You have %d coins of 1p which means you have %d",a1,n1); // it looks like we have to use only printf and not lcd.printf
       wait(3);
       lcd.cls();
       //doing these things for the other coins as well
       
       //ta = n1+n2+n5+n10+n20+n50+n100+n200;
       lcd.printf("Your total amount is %d",ta);
       wait(3);
       lcd.cls();
       
       /*if() //press button or something like that 
       {
           lcd.printf("Please enter the mount of money you took:");
           scanf("%f",&tm);
           lcd.printf("%f",tm);
           wait(2);
           ta = ta-tm;
           lcd.printf("Now you have only %f \bx156 left", ta); //\b for one step backword and I guess that x156 for £ //I'm not sure
       }*/
       
    return(0);
}