Important changes to forums and questions
All forums and questions are now archived. To start a new conversation or read the latest updates go to forums.mbed.com.
6 years, 5 months ago.
Why does the mbed hang when I don't duplicate an interrupt function in main()?
I have an odd error I can't get my head around...
I have an interrupt, and SD card interfaced use the SDBlockDevice (sd-driver) library in an official mbed Git repo (but not part of mbed-os).
I have a function 'TRIG' which opens a file, writes to it and closes it. The TRIG function is called by an interrupt.
If I call it, the mbed hangs with a flashing LED (4 slow pulses, 4 fast pulses)...
HOWEVER!
If I have the same function statements in the main() AND the TRIG (as shown below), the interrupt works and writes to the SD card!!!
I am completely confused about what is happening here?
CODE THAT WORKS:
void TRIG() {
wait(1);
FILE* fy = fopen("/sd/number.txt", "a");
wait(1);
fprintf(fy, "test4343\n");
fclose(fy);
}
int main() {
wait(1);
FILE* fd = fopen("/sd/number.txt", "a");
wait(1);
fprintf(fd, "test\n");
fclose(fd);
switch_a.rise(&TRIG);
CODE THAT DOESN'T WORK:
void TRIG() {
wait(1);
FILE* fy = fopen("/sd/number.txt", "a");
wait(1);
fprintf(fy, "test4343\n");
fclose(fy);
}
int main() {
switch_a.rise(&TRIG);