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7 years, 5 months ago.
It looks like PA_12 can't be an Interrupt IN
Every thing is in the title... It's written that all pins can be InterruptIn but test on PA_12 are showing the exact opposite !
How to be ripped off
Serial Pc (PA_2, PA_3, 460800);
DigitalOut Trig1 (PC_3);
DigitalOut Trig2 (PC_2);
DigitalOut Trig3 (PA_9);
DigitalOut Led1 (PA_5);
DigitalOut Led2 (PD_2);
InterruptIn Echo1 (PA_12);
InterruptIn Echo2 (PA_11);
InterruptIn Echo3 (PB_12);
Ticker timer;
Timer temps;
int FlagUS1 = 0, FlagUS2 = 0, FlagUS3 = 0;
long Echo1Start, Echo2Start, Echo3Start;
double DistUS1, DistUS2, DistUS3;
void echo1Rise ()
{
Echo1Start = temps.read_us();
}
void echo2Rise ()
{
Echo2Start = temps.read_us();
Led2 = !Led2;
}
void echo3Rise ()
{
Echo3Start = temps.read_us();
}
void echo1Fall ()
{
DistUS1 = (double)(temps.read_us() - Echo1Start)/5.8;
FlagUS1 = 1;
}
void echo2Fall ()
{
DistUS2 = (double)(temps.read_us() - Echo2Start)/5.8;
FlagUS2 = 1;
}
void echo3Fall ()
{
DistUS3 = (double)(temps.read_us() - Echo3Start)/5.8;
FlagUS3 = 1;
}
void tickTime()
{
Tick++;
FlagTick = 1;
if ((Tick%100)==0) FlagTickLed = 1;
}
int main()
{
temps.reset();
temps.start();
timer.attach(&tickTime, 0.001);
Echo1.rise (&echo1Rise);
Echo2.rise (&echo2Rise);
Echo3.rise (&echo3Rise);
Echo1.fall (&echo1Fall);
Echo2.fall (&echo2Fall);
Echo3.fall (&echo3Fall);
Echo1.enable_irq();
Echo2.enable_irq();
Echo3.enable_irq();
Led2 = 0;
Led1 = 0;
while (1) {
do {
if (FlagTickLed) {
Led1 = !Led1;
FlagTickLed = 0;
}
// Gestion des US
if (((Tick%150)==0) && FlagTick) {
Trig1 = 1;
wait_us(15);
Trig1 = 0;
FlagTick = 0;
}
if (((Tick%150)==50) && FlagTick) {
Trig2 = 1;
wait_us(15);
Trig2 = 0;
FlagTick = 0;
}
if (((Tick%150)==100) && FlagTick) {
Trig3 = 1;
wait_us(15);
Trig3 = 0;
FlagTick = 0;
}
if (FlagUS1==1) {
Pc.printf ("\rUS 1 = %04d mm", (int)DistUS1);
FlagUS1 = 0;
}
if (FlagUS2==1) {
Pc.printf ("\r\t\t\tUS 2 = %04d mm", (int)DistUS2);
FlagUS2 = 0;
}
if (FlagUS3==1) {
Pc.printf ("\r\t\t\t\t\t\tUS 3 = %04d mm", (int)DistUS3);
FlagUS3 = 0;
}
} while(!Pc.readable());
}
}
Does Anyone experience the same problem ?
Question relating to:
1 Answer
7 years, 5 months ago.
If you look at the datasheet you'll see that PA_12 *can* in fact be an interrupt in. However it also states that only *one* source per numeric-input can be provided to the interrupt-input multiplexer. The problem you are having is that you created an instance of InterruptIn Echo3(PB_12). This will cause the initializer to switch the 12th source interrupt input over to PB_12. Try commenting out Echo3 and see if Echo1 starts working. Then you will need to find an appropriate available input on a different numeric input for Echo3.
In other words: PA_12 or PB_12 or PC_12 or PD_12 (etc..) can be the 12th external interrupt source. But only *one* of those inputs! Choose another numeric input for the next interrupt etc..