Ziga Lausegger

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9 years, 7 months ago.

LPC4088 quick start board

I am deciding on buying an LPC4088 quick start board and I want to know something. When I select "LPC4088 quick start board" in the compiler, what does this do to the project? Does it:

  • supply appropriate "linker script",
  • supply appropriate "makefile",
  • supply appropriate "startup file"?

To which function does a startup file jumps - is it named "main()" or "c_entry()" or possibly something else?

When I worked on my LPC3141, I wrote programs (more like simple drivers) like the one below. In case of my LPC3141 "startup code" expected function "c_entry()" instead of "main()". I just defined pointers to my registers and toggled them easily. Could I use the same principle with LPC4088?

simplest LPC3141 example - source.c

#define GPIO_MODE0 (*((volatile unsigned int *) 0x130031D0))
#define GPIO_MODE1 (*((volatile unsigned int *) 0x130031E0))
#define GPIO_MODE0_SET (*((volatile unsigned int *) 0x130031D4))
#define GPIO_MODE1_SET (*((volatile unsigned int *) 0x130031E4))
#define GPIO_MODE0_RESET (*((volatile unsigned int *) 0x130031D8))
#define GPIO_MODE1_RESET (*((volatile unsigned int *) 0x130031E8))

void delay(void);

void c_entry(void){

	GPIO_MODE1_SET = 0x4000;

	while(1){
		GPIO_MODE0_SET = 0x4000;
		delay();
		GPIO_MODE0_RESET = 0x4000;
		delay();
	}
}

void delay(void){
	volatile int stej = 1000000;
	while(count){
		count = count - 1;
	}
}
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