10 years, 3 months ago.

I still cant recieve a call from the GPRS

im using the same code but still I cant receive a call!!

/* Copyright (c) 2010-2011 mbed.org, MIT License

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• and associated documentation files (the "Software"), to deal in the Software without
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• BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND
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1. include "mbed.h"
2. include "GSM.h"

1. define PHONE_NUMBER "00447*74"

1. define SEND_SMS_TEST 1
2. define CALL_UP_TEST 1
3. define ANSWER_TEST 0
4. define READ_SMS_TEST 0

/ On many platforms USBTX/USBRX overlap with serial on D1/D0 pins and enabling the below will interrupt the communication.

• You can use an LCD display to print the values or store them on an SD card etc.
• / Serial pc(USBTX, USBRX);

/**

• D1 - TX pin (RX on the GSM module side)
• D0 - RX pin (TX on the GSM module side)
• 19200 - GSM baud rate
• / GSM gsm(p9, p10, 19200, PHONE_NUMBER);

void messageHandle(void) { disable_irq(); int messageType = gsm.loopHandle(); if(MESSAGE_RING == messageType) { gsm.answer(); } else if(MESSAGE_SMS == messageType) { char smsMessage[SMS_MAX_LENGTH]; gsm.getSMS(smsMessage); } enable_irq(); }

int main(void) { while(0 != gsm.init()) { wait(2); }

1. if SEND_SMS_TEST gsm.sendSMS(PHONE_NUMBER, "Hello from my GPRS shield");
2. endif

1. if CALL_UP_TEST gsm.callUp(PHONE_NUMBER);
2. endif

1. if ANSWER_TEST || READ_SMS_TEST gsm.gsmSerial.attach(&messageHandle);
2. endif

while(1) { wait(1); } }

Do I have to do something with the serial Serial pc(USBTX, USBRX) with the D0,D1 because its written that its usually overlapped?

Question relating to:

Last updated: 13 Feb 2015

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/ Seeed_GPRS_Shield_GSM

GSM example program for the SeeedStudio GPRS Shield V2.0, based on UART serial port connectivity (D0/D1 pins). This program uses a GSM library to dial a number, send SMS, read … GPRS, GSM, shield