File content as of revision 4:e0b82f12f958:

#include "mbed.h"
#include "C12832.h"


C12832 lcd(p5, p7, p6, p8, p11);

/*int main()
{
    int j=0;
    lcd.cls();
    lcd.locate(0,3);
    lcd.printf("mbed application board!");

    while(true) 
    {   // this is the third thread
        lcd.locate(0,15);
        lcd.printf("Counting : %d",j);
        j++;
        wait(1.0);
    }
}*/


int main() 
{
    int n1=0; //number of 1p coins
    float a1=0; //amount of 1p coins
    //...
    float ta=0; //total amount of all coins
    int c=0; //counting variable
    //float tm; // token money 
    
  /*  for(;;)
    {
       if(LDR1 == 1)
       {
        a1++;
        n1 = a1*0.01;
        //wait(0.2); //I don't know if the programm would count a coin twice when we reset the LED immediately because the programm runs faster than the coins fall 
        //why is LED1 = 0; a failure?
        c = 0;
       }
       //... other types of coins
       c++;
       if (c >= 100)//depands how long the programm per cycle needs
       {
           break;
       }
    } */
       lcd.printf("You have %d coins of 1p \nwhich means you have %d$*ps",a1,n1); // it looks like we have to use only printf and not lcd.printf
       wait(5);
       lcd.cls();
       //doing these things for the other coins as well
       
       //ta = n1+n2+n5+n10+n20+n50+n100+n200;
       lcd.locate(0,0);
       lcd.printf("Your total amount is %d",ta);
       wait(5);
       lcd.cls();
       
       /*if() //press button or something like that 
       {
           lcd.printf("Please enter the mount of money you took:");
           scanf("%f",&tm);
           lcd.printf("%f",tm);
           wait(2);
           ta = ta-tm;
           lcd.printf("Now you have only %f \bx156 left", ta); //\b for one step backword and I guess that x156 for £ //I'm not sure
       }*/
       
    return(0);
}